Respuesta :
Complete question is;
A square pyramid has side lengths each measuring 8 centimeters. The height of the pyramid is 3 centimeters. What is the lateral area of the pyramid?
Answer:
Lateral area = 80 cm²
Step-by-step explanation:
We are given;
Side length; a = 8 cm
Height of pyramid; h = 3 cm
Now, formula for Lateral area of pyramid = ½ × p × L
Where p is perimeter of base and L is slant length.
Since we know the side length and height of pyramid, we can find the slant height using Pythagoreas theorem.
L² = (½×side length)² + h²
L² = (½×8)² + 3²
L² = 16 + 9
L = √25
L = 5 cm
Now perimeter of square base = 4a = 4 x 8 = 32cm
So,
Lateral area = ½ × p × L = ½ × 32 × 5
Lateral area = 80 cm²
Answer:
80 square centimeters
Step-by-step explanation:
we need to find the hypotenuse or the slant height of the triangle so 3^2+4^2 = the square root of 25 = 5
We got 4 because half of 8 is 4 and we are basically cutting the triangle in half because the height (3) is perpendicular to the side length.
8(5)/2 = 20
20(4) = 80
