Answer:
The equation of the hyperbola is:
[tex]\frac{x^{2}}{76} - \frac{y^{2}}{12} = 1[/tex]
Step-by-step explanation:
The equation of a hyperbola centered in the origin in standard form is:
[tex]\frac{x^{2}}{a^{2}}-\frac{y^{2}}{b^{2}} = 1[/tex]
The distance between both vertexes is equal to:
[tex]2\cdot b = \sqrt{(0-0)^{2}+(\sqrt{12}+\sqrt{12})^{2}}[/tex]
[tex]2\cdot b = 2\cdot \sqrt{12}[/tex]
[tex]b = \sqrt{12}[/tex]
Now, the distance between any of the vertexes and origin is:
[tex]c = \sqrt{(0-0)^{2}+[(4-(-4)]^{2}}[/tex]
[tex]c = 8[/tex]
The remaining parameter of the hyperbola is determined by the following Pythagorean expression:
[tex]c^{2} = a^{2} - b^{2}[/tex]
[tex]a = \sqrt{c^{2}+b^{2}}[/tex]
[tex]a = \sqrt{64+12}[/tex]
[tex]a = \sqrt{76}[/tex]
The equation of the hyperbola is:
[tex]\frac{x^{2}}{76} - \frac{y^{2}}{12} = 1[/tex]
Answer:
The equation of the hyperbola is:
x²/76 - y²/12 = 1
Step-by-step explanation:
The standard for of an equation of a hyperbola centered in the origin is given as:
x²/a² - y²/b² = 1
The distance between both vertexes is:
2b, where b = √12
The distance between any of the vertexes and origin is:
c = 8
But a² = b² + c² (Pythagoras rule)
c² = a² - b²
8² = a² - 12
a² = 64 + 12 = 76
a = √76
Therefore, the equation of the hyperbola is:
x²/76 - y²/12 = 1
