Answer:
2a) [tex]1\frac{7}{16}[/tex]
2b) [tex]\frac{5}{48}[/tex]
Step-by-step explanation:
The first thing we need to do is add all the fractions together so,
2a) [tex]2\frac{1}{2} +3\frac{3}{16}+\frac{7}{8}[/tex]
We need to find the LCM of the denominators in order to properly add the fractions together so the LCM is 16
[tex]2\frac{1}{2} +3\frac{3}{16}+\frac{7}{8}[/tex] = [tex]2\frac{8}{16} +3\frac{3}{16} +\frac{14}{16} = 5\frac{25}{16} =6\frac{9}{16}[/tex]
Now we subtract this from 8 as asked in the question,
[tex]8-6\frac{9}{16} =\frac{8}{1} -\frac{105}{16} =\frac{128}{16} -\frac{105}{16}=\frac{23}{16} =1\frac{7}{16}[/tex]
2b) We are asked to minus the fraction [tex]1\frac{7}{16}[/tex] from [tex]1\frac{1}{3}[/tex]
Find the common denominator which is 48
[tex]1\frac{7}{16} -1\frac{1}{3} =1\frac{21}{48} -1\frac{16}{48} =\frac{5}{48}[/tex]
