Answer:
282.7KPa
Explanation:
Step 1:
Data obtained from the question.
Number of mole of (n) = 1.5 mole
Volume (V) = 13L
Temperature (T) = 22°C = 22 + 273°C = 295K
Pressure (P) =..?
Gas constant (R) = 0.082atm.L/Kmol
Step 2:
Determination of the pressure exerted by the gas.
This can be obtained by using the ideal gas equation as follow:
PV = nRT
P = nRT /V
P = 1.5 x 0.082 x 295 / 13
P = 2.79atm.
Step 3:
Conversion of 2.79atm to KPa.
This is illustrated below:
1 atm = 101.325KPa
Therefore, 2.79atm = 2.79 x 101.325 = 282.7KPa
Therefore, the pressure exerted by the gas in KPa is 282.7KPa
Pressure is defined as the force exerted by the molecules colliding with the surface of the object and other surfaces. The ideal gas follows the general gas law equation, PV = nRT.
The pressure exerted by the gas is 282.7 KPa.
Given:
Pressure (P) = ?
Gas constant (R) = 0.082atm.L/Kmol
Temperature (T) = 22°C = 22 + 273°C = 295K
Volume (V) = 13L
Number of mole of (n) = 1.5 mole
Now, using the ideal gas equation:
PV = nRT
Substituting the values, we get:
P x 13 = 1.5 x 0.082 x 295
P x 13 = 36.285
P = [tex]\dfrac{36.285}{13}[/tex]
Pressure = 2.79 atm.
Also, 1 atm = 101.32 KPa
2.79 atm = 2.79 x 101.32 = 282.7 KPa.
Thus, the pressure exerted by the gas molecules is 282.7 KPa.
To know more about ideal gas law, refer to the following link:
https://brainly.com/question/12124605
