Answer:
The minimum number of adult tickets required to be sold = 54
Step-by-step explanation:
Hello,
In this question, we have several variables which might confuse us here, so I'll have to break it down bit by bit.
The drama club must make a sale of $560 so as to cover cost for the event.
The seat capacity of the hall = 84
Cost of tickets for adult = $8
Cost of tickets for students = $4.50
Total number of students sold = 29
Let the number of adult ticket required = x.
(4.50 × 29) + (8 × x) = 560
130.5 + 8x = 560
8x = 560 - 130.5
8x = 429.5
Divide both sides by 8
X = 429.5 / 8
X = 53.6 approximately 54.
Minimum required number of adult tickets to be sold is 54.
(29 × 4.50) + (54 × 8) = $130.5 + $432 = $562.5
