Answer:
Following are the ratio to this question:
Step-by-step explanation:
Given:
[tex]\bold{\tan \phi = \frac{60}{11} }\\\\[/tex]
Formula:
[tex]\sin \phi = \frac{Perpendicular}{Hypotenuse}\\\\\cos \phi = \frac{Base}{Hypotenuse} \\\\\tan \phi = \frac{Perpendicular}{Base} \\\\\ cosec \phi = \frac{Hypotenuse}{Perpendicular}\\\\\sec \phi =\frac{Hypotenuse}{Base}\\\\\cot \phi = \frac{Base}{Perpendicular}\\\\[/tex]
[tex]\ Base = 11 \\\ Perpendicular =60\\\ Hypotenuse= 61\\[/tex]
[tex]\sin \phi = \frac{60}{61}\\\\\cos \phi = \frac{11}{61} \\\\\tan \phi = \frac{60}{11} \\\\\ cosec \phi = \frac{ 61}{60}\\\\\sec \phi =\frac{61}{11}\\\\\cot \phi = \frac{11}{60}\\\\[/tex]
