Select all polynomials that are divisible by (x + 3).

Choose all answers that apply:

© A(x)= x3 + 4x2 – 9

® B(x) = x3 – 22 – 18

© C(x) = x3 – 6x – 9

© D(x) = x3 + 3x +3

Respuesta :

Answer:

x³+4x²-9

Step-by-step explanation:

x+3=0

x=-3

put x=-3 into x³+4x²-9, if it is equal to zero then it is dividsble

so, (-3)³+4(-3)-9=0

so a is correct

The polynomial A(x) is divisible by (x+3).

What is factor?

A factor is a number or expression that divides another number or expression  leaving no remainder.

What is factor theorem?

If p(x) be the polynomial, then p(x) is divisible by q if q is the factor of p(x).

According to the given question

we have different polynomials

[tex]A(x) = x^{3} +4x^{2} -9[/tex]        

When we divide A(x) by (x+3) we get remainder 0.

⇒ (x+3) is a factor of A(x).

Hence, the polynomial  A(x) is divisible by (x+3).

[tex]B(x) = x^{3} -22 -18[/tex]

⇒ [tex]B(x) = x^{3} -30[/tex]

When we divide B(x) by (x+3) we get remainder -57.

⇒ (x+3) is not a factor of B(x)

Hence, the polynomial B(x) is not divisible by (x + 3).

[tex]C(x) =x^{3} -6x -9[/tex]

By dividing C(x) by (x +3)  we get remainder -18

⇒ (x+3) is not a factor of C(x).

Hence, C(x) is not divisible by (x+3).

[tex]D(x) = x^{3} + 3x + 3[/tex]

By dividing  D(x) by (x+3), we get remainder -33.

⇒ (x+3) is not a factor of D(x).

Hence, D(x) is not divisible by (x+3).

Thus, the polynomial A(x) is divisible by (x+3).

Learn more about factor theorem here:

https://brainly.com/question/12959513

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