Answer:
Fc = 19.2 N
Explanation:
In this case, the force of the Honda over the rock, is a centripetal force. Then, you have:
[tex]F_c=m\frac{v^2}{r}[/tex]
m: mass of the rock = 600g = 0.6 kg
v: tangential velocity of the Honda = 4m/s
r: radius of the Honda = 50cm = 0.5m
You replace the values of m, r and v in the equation for Fc:
[tex]F_c=(0.6kg)\frac{(4m/s)^2}{0.5m}\\\\F_c=19.2N[/tex]
hence, the force has a magnitude of 19.2 N
If the rock would have more mass the centripetal force would be higher
