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1. How many moles of a gas are contained in a 101 liter flask at a pressure of 2.0 atm and a temperature of 600K? (R = 0.0821)


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Respuesta :

sebassandin

Answer:

[tex]n=4.1mol[/tex]

Explanation:

Hello,

In this case, we can use the ideal gas equation:

[tex]PV=nRT[/tex]

So we know the temperature, pressure and volume, therefore we can easily compute the required moles as shown below:

[tex]n=\frac{PV}{RT}=\frac{2.0atm*101L}{0.082\frac{atm*L}{mol*K}*600K} \\\\n=4.1mol[/tex]

Best regards.

Eduard22sly

Answer:

4.1 moles

Explanation:

The following data were obtained from the question.

Number of mole (n) =..?

Volume (V) = 101L

Pressure (P) = 2atm

Temperature (T) = 600K

Gas constant (R) = 0.0821atm.L/Kmol

The number of mole of the gas can be obtained by using the ideal gas equation as illustrated below:

PV = nRT

2 x 101 = n x 0.0821 x 600

Divide both side by 0.0821 x 600

n = (2x 101) / (0.0821 x 600)

n = 4.1 moles.

Therefore, the number of mole of the gas in the container is 4.1 moles

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