Answer:
The ball will hit the ground at 0.968 seconds.
Step-by-step explanation:
Please refer to the attached graph in the answer area.
The given equation of height according to input variable time 't' is:
[tex]h = - 16 t^{2} + 15 ...... (1)[/tex]
h is in feet
t is in seconds
Both the values 't' and 'h' will be positive. (Time and height can never be negative)
To determine the time, at which the ball hits the ground, i.e. the height becomes 0.
Putting value of h = 0 in equation (1)
[tex]0 = - 16 t^{2} + 15 \\\Rightarrow t^{2} = \dfrac{15}{16}\\\Rightarrow t = \sqrt{\dfrac{15}{16}}\\\Rightarrow t = 0.968\ sec[/tex]
Hence, the time at which the ball hits the ground is 0.968 seconds.
