Corrected Question
One cylinder has a volume that is 8cm less than 7/8 of the volume of a second cylinder. If the first cylinder’s volume is 216cm³, what is the correct equation and value of x, the volume of the second cylinder?
Answer:
The equation is: [tex]216=\frac{7}{8}x-8[/tex]
Volume of the second cylinder= [tex]256cm^3[/tex]
Step-by-step explanation:
Volume of the first cylinder=[tex]216cm^3[/tex]
Let the volume of the second cylinder=x
7/8 of the volume of a second cylinder=[tex]\frac{7}{8}x[/tex]
8 less than 7/8 of the volume of a second cylinder=[tex]\frac{7}{8}x-8[/tex]
Therefore, the equation is:
[tex]216=\frac{7}{8}x-8[/tex]
Next, we solve for x
[tex]216=\frac{7}{8}x-8\\216+8=\frac{7}{8}x\\224=\frac{7}{8}x\\$Cross multiply\\7x=224*8\\Divide both sides by 7\\x=256cm^3[/tex]
The volume of the second cylinder is [tex]256cm^3[/tex]
