Answer:
36
Step-by-step explanation:
In circle with center O,
[tex] chord\overline {EF} \cong chord\overline {WV}... (Given) [/tex]
Since, congruent chords are equidistant from the center of the circle.
[tex] \therefore PG = GO\\
\therefore - x +10 = - 3(x+2)\\
\therefore - x + 10 = - 3x - 6\\
\therefore 3x - x = - 6-10\\
\therefore 2x = - 16\\\\
\therefore x = \frac{-16}{2} \\\\
\huge \red {\boxed {\therefore x = - 8}} \\\\
\because \overline {PO} = \overline {PG} + \overline {GO} \\
\therefore \overline {PO} = - x + 10 + \{-3(x + 2)\}\\
\therefore \overline {PO} = - x + 10 - 3x - 6\\
\therefore \overline {PO} = - 4x + 4 \\
\therefore \overline {PO} = - 4\times (-8)+ 4 \\
\therefore \overline {PO} =32+ 4 \\
\huge \orange {\boxed {\therefore \overline {PO} =36}} \\[/tex]
