Respuesta :
Answer:
Explanation:
Consider the given reaction,
A+B +C
[tex]rate=k[A]^m[B]^m[/tex]
Reaction is first order with respect to reactant B.
The pseudo order rate is
[tex]rate=k_1 [B]^m,\\\\where k_1 =k[A]^m[/tex]
Pseudo order reaction is the reaction in which the reactant concentration remains constant; its concentration is very high so it does not involve in the rate of the reaction. Here, the concentration of A is sufficiently high so this reaction becomes the pseudo first order reaction.
The reaction is first order with respect to [B] with rate constant k1 .
Using the given table, concentration of B is decreasing the rate also decreasing
Therefore, order of the reaction with respect to A is 1.
Value of m is 1.
The order of the reaction in reactant A is 1, means the value of m for given rate should be 1.
What is pseudo order reaction?
Pseudo order reactions are those reactions in which two reactants are present but the concentration of one of the reactant is present in excess quantity and it seems like first order reaction.
Given chemical reaction is: A + B +C
According to the question, given reaction is first order with respect to the reactant B and rate law will be represented as:
Rate = k[A]m[B]m
Also given that reactant A is present in high concentration in the reaction, so the rate of pseudo order reaction is:
Rate = k1[B]n, where
k1 = k[A]m
According to the given table with respect to concentration of reactant B and rate k1, it is clear that rate of the reaction decreases as the concentration of reactant B decreses. So, to get the required result order of the reaction or value of m with respect to the reactant A should be 1.
Hence option (B) is correct i.e. 1.
To know more about pseudo order reaction, visit the below link:
https://brainly.com/question/5524713
