Answer:
Two real solutions
Step-by-step explanation:
We have the equation [tex]u^2=80[/tex]
To get a solution, we must solve for u.
When we solve for u, we need to square root each side, but when we do this, we must add a ± to the side that opposite to the u in order to compensate. This is because you could get 80 in two different ways:
[tex](\sqrt{80} )(\sqrt{80})=80 \\\\(-\sqrt{80} )(-\sqrt{80})=80[/tex]
This would mean that when we solve for u, we would get [tex]u=[/tex] ± [tex]\sqrt{80}[/tex]
Which is the same thing as [tex]u=\sqrt{80}[/tex] and [tex]u=-\sqrt{80}[/tex]
Which are two real solutions.
