Answer:
Cosθ = 0.5145
Sinθ = 0.8575
Secθ = 1.9436
tanθ = 1.667
Step-by-step explanation:
From the figure attached,
Point P(-3, 5) is on the terminal side and AB is the initial side of the angle PAB.
If m∠PAB = θ
AB = [tex]\sqrt{(3)^{2}+(5)^{2}}[/tex]
= [tex]\sqrt{34}[/tex]
= 5.831
Then Cosθ = [tex]\frac{AB}{AP}[/tex] = [tex]\frac{3}{5.831}[/tex]
Cosθ = 0.5145
Sinθ = [tex]\frac{PB}{AP}[/tex]
Sinθ = [tex]\frac{5}{5.831}[/tex]
Sinθ = 0.8575
Secθ = [tex]\frac{1}{\text{Cos}\theta}[/tex]
Secθ = [tex]\frac{1}{0.5145}[/tex]
Secθ = 1.944
tanθ = [tex]\frac{PB}{AB}[/tex]
tanθ = [tex]\frac{5}{3}[/tex]
tanθ = 1.667
