Answer:
Equation of circle is [tex]x^2+y^2-12x-4y+24=0[/tex]
None of the options is correct
Step-by-step explanation:
Given: Graph
To find: equation of circle
Solution:
A circle is a locus of all points that are at a fixed distance (radius) from a fixed point (centre).
From the graph,
centre (a, b) = [tex]\left ( 6,2 \right )[/tex]
radius (r) = 4 units
Equation of circle is of form [tex](x-a)^2+(y-b)^2=r^2[/tex]
[tex](x-6)^2+(y-2)^2=4^2\\x^2+36-12x+y^2+4-4y=16\\x^2+y^2-12x-4y+24=0[/tex]
The equation of circle is [tex]x^2+y^2-12x-4y+24=0[/tex]
None of the options is correct
We have given the graph
We have to determine the equation of circle
A circle is a locus of all points that are at a fixed distance (radius) from a fixed point (centre).
From the graph,
centre (a, b) = (6,2)
radius (r) = 4 units
Equation of circle is of form
[tex](x-a)^2+(y-b)^2=r^2[/tex]
[tex](x-6)^2+(y-2)^2=4^2\\x^2-12x+36+y^2-4y+4=16\\x^2+y^2-12x-4y+24=0[/tex]
Therefore the equation of the circle is [tex]x^2+y^2-12x-4y+24=0[/tex]
To learn more about the circle visit:
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