A circle is centered at O(0,0)O(0,0)O, left parenthesis, 0, comma, 0, right parenthesis and has a radius of \sqrt{29}


29





square root of, 29, end square root.


Where does the point T(5,-2)T(5,−2)T, left parenthesis, 5, comma, minus, 2, right parenthesis lie?

Respuesta :

Answer:

Point T is on the circle

Step-by-step explanation:

To check where the point lies, we need to find its distance to the center of the circle.

The distance between two points (x1, y1) and (x2, y2) is given by:

[tex]distance = \sqrt[2]{(x2 - x1)^{2} + (y2 - y1)^{2}}[/tex]

If the first point is O(0,0) and the second is T(5, -2), we have:

[tex]distance = \sqrt[2]{(5 - 0)^{2} + (-2 - 0)^{2}}[/tex]

[tex]distance = \sqrt{29}[/tex]

The distance between the points is equal the radius of the circle, that means the point T is on the circle.

Answer:

inside the circle

Step-by-step explanation:

Khan Academe