Respuesta :
Answer:
The final temperature of the water is 28.98 degree Celsius.
Explanation:
It is given that,
Mass of sample of water, m = 52 grams
Initial temperature, [tex]T_i=10^{\circ}C[/tex]
Heat absorbed, [tex]Q=4,130\ J[/tex]
The specific heat of water is [tex]4.184\ J/(g^{\circ} C)[/tex]
We need to find the final temperature of the water. The heat absorbed is given by the formula as follows :
[tex]Q=mc\Delta T\\\\Q=mc(T_f-T_i)\\\\T_f=\dfrac{Q}{mc}+T_i\\\\T_f=\dfrac{4130}{52\times 4.184 }+10\\\\T_f=28.98^{\circ} C[/tex]
So, the final temperature of the water is 28.98 degree Celsius.
Answer:
29 degree Celsius
Explanation:
If anyone confused this is the choices:
11 °C
19 °C
29 °C
Estimate 28.98 to 29 for the answer
