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Cosine is the square root of 3 over 2. How do I find the secant expression without a square root in the denominator by rationalizing the denominator?

Respuesta :

caylus
Hello,

[tex]cos(x)= \dfrac{ \sqrt{3} }{2} \\ sec(x)= \dfrac{1}{cos(x)} = \dfrac{1}{\dfrac{ \sqrt{3} }{2}} =\dfrac{ 2*\sqrt{3} }{\sqrt{3}*\sqrt{3}}=\dfrac{2*\sqrt{3}}{3}[/tex]
jhonyy9
than cos = sqrt3 /2 so 

sec = 1/(sqrt3 /2)

sec = 2/sqrt3 

sec = 2sqrt3 /3

hope helped 

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