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Algebra 2 Help!

What are the sine, cosine, and tangent of 5pi/3 radians?

sin Θ = -sqrt 3/2; cos Θ = 1/2; tan Θ = -sqrt 3

sin Θ = sqrt 3/2; cos Θ = -1/2; tan Θ = sqrt 3

sin Θ = sqrt 3/2; cos Θ = 1/2; tan Θ = sqrt 3

sin Θ = -sqrt 3/2; cos Θ = -1/2; tan Θ = -sqrt 3

Respuesta :

meerkat18
Base on the question that ask to calculate the sine, cosine, and tangent of 5pi/3 radians and base on my further calculation, I would say that the answer would be sin Θ = -sqrt 3/2; cos Θ = -1/2; tan Θ = -sqrt 3. I hope you are satisfied with my answer and feel free to ask for more if you have question and further clarification 
calculista

Answer:

[tex]sin(\frac{5\pi }{3})=-\frac{\sqrt{3}}{2}[/tex] ; [tex]cos(\frac{5\pi }{3})=\frac{1}{2}[/tex] ; [tex]tan(\frac{5\pi }{3})=-\sqrt{3}[/tex]

Step-by-step explanation:

we know that

[tex]\pi \ radians=180\ degrees[/tex]

so

[tex]\frac{5\pi }{3}\ radians=300\ degrees[/tex]

The angle belong to the IV quadrant

therefore

The sine is negative

The cosine is positive

The tangent is negative

[tex]360\°-300\°=60\°[/tex]

so

[tex]sin(\frac{5\pi }{3})=-sin(60\°)=-\frac{\sqrt{3}}{2}[/tex]

[tex]cos(\frac{5\pi }{3})=cos(60\°)=\frac{1}{2}[/tex]

[tex]tan(\frac{5\pi }{3})=-tan(60\°)=-\sqrt{3}[/tex]

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