Answer:
The charge stored is [tex]Q = 4.25 *10^{-7 } \ C[/tex]
The energy stored is [tex]E = 2.55*10^{-6} \ J[/tex]
Explanation:
From the question we are told that
The area of the plates is [tex]A = 0.40 \ m^2[/tex]
The separation between the plate is [tex]d = 0.10 \ mm =0.0001 \ m[/tex]
The potential difference is [tex]V = 12 \ V[/tex]
The permitivity of free space is [tex]\epsilon_o = 8.85 *10^{-12} C^2 \cdot N^{-1} \cdot m^2[/tex]
The dielectric constant of glass is K = 5.0
Generally the capacitance of this capacitor is
[tex]C = \frac{\epsilon_o * A}{d}[/tex]
substituting values
[tex]C = \frac{8.85*10^{-12} * 0.40}{0.0001}[/tex]
[tex]C = 3.34 *10^{-8} \ C[/tex]
The charge stored is mathematically evaluated as
[tex]Q = CV[/tex]
substituting values
[tex]Q = (3.54*10^{-8} * 12)[/tex]
[tex]Q = 4.25 *10^{-7 } \ C[/tex]
The energy stored is
[tex]E = 0.5 * CV^2[/tex]
substituting values
[tex]E = 0.5 * (4.25 *10^{-7} * 12^2)[/tex]
[tex]E = 2.55*10^{-6} \ J[/tex]
