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a cooler contains 50 bottles; 30 bottles of water, which 8 are lemon flavored and 20 bottles of tea, of which 5 are lemon flavored. if you randomly select two beverages. what is the probability that both beverages are lemon flavored and 1 beverage is water and other is tea

Respuesta :

Answer:

The required probability is [tex]\dfrac{13}{50}[/tex]

Step-by-step explanation:

Total number of bottles = 50

Total number of water bottles = 30

Total number of lemon flavored water bottles = 8

Total number of tea bottles = 20

Total number of lemon flavored tea bottles = 5

Probability of selecting a lemon flavored water bottle = Probability of selecting a water bottle [tex]\times[/tex] Probability of selecting a lemon bottle out of water bottles.

Probability of selecting a lemon flavored tea bottle = Probability of selecting a tea bottle [tex]\times[/tex] Probability of selecting a lemon bottle out of tea bottles.

Formula for probability of an event E can be observed as:

[tex]P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}[/tex]

Probability of selecting a water bottle:

[tex]\dfrac{30}{50} = \dfrac{3}{5}[/tex]

Probability of selecting a lemon flavored bottle from water bottle:

[tex]\dfrac{8}{30}[/tex]

Probability of selecting a lemon flavored water bottle = P(A)

[tex]\dfrac{3}{5} \times \dfrac{8}{30} = \dfrac{4}{25}[/tex]

Probability of selecting a tea bottle:

[tex]\dfrac{20}{50} = \dfrac{2}{5}[/tex]

Probability of selecting a lemon flavored bottle from tea bottle:

[tex]\dfrac{5}{20} = \dfrac{1}{4}[/tex]

Probability of selecting a lemon flavored tea bottle = P(B)

[tex]\dfrac{2}{5} \times \dfrac{1}{4} = \dfrac{1}{10}[/tex]

The required probability is:

P(A) + P(B):

[tex]\dfrac{4}{25} + \dfrac{1}{10}\\\Rightarrow \dfrac{8+5}{50}\\\Rightarrow \dfrac{13}{50}[/tex]