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A circular disk of radius 2.0 m rotates, starting from rest, with a constant angular acceleration of 20.0 rad/s2 . What is the tangential acceleration of a point on the edge of the disk at the instant that its angular speed is 1.0 rev/s

Respuesta :

Answer:

  a = 40 m / s²

Explanation:

This is a kinematics problem, where we must use both linear and angular and the relationship between them

we'll eat by reducing the angular velocity to units if

      w = 1.0 rev / s (2pi rad / 1 rev) = 2pi rad / s

they ask us for linear acceleration, we use the relationships between linear or angular variables

       a = α R

       a = 20  2

       a = 40 m / s²

abidemiokin

The tangential acceleration of a point on the edge of the disk at the instant that its angular speed is 1.0 rev/s is 40m/s²

The formula for calculating the tangential acceleration is expressed as:

  • [tex]a=\alpha R[/tex]
  • [tex]\alpha[/tex] is the angular acceleration
  • R is the radius of the disk

Given the following parameters:

  • [tex]\alpha[/tex] = 20.0 rad/s²
  • r = 2.0m

Substitute the given parameters into the formula;

[tex]a=\alpha R\\a=20 \times 2\\a = 40m/s^2[/tex]

Hence the tangential acceleration of a point on the edge of the disk at the instant that its angular speed is 1.0 rev/s is 40m/s²

Learn more on tangential acceleration here: https://brainly.com/question/390784

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