The arithmetic mean (average) of four numbers is 85. If the largest of these numbers is 97, find the mean of the remaining three numbers.

Respuesta :

Answer: A) = 81

Step-by-step explanation:

Say that the four numbers are a,b,c & 97.

Then a+b+c+97/4 = 85

a+b+c+97=340

a+b+c=243

a+b+c/3 = 81

The average of the remaining three numbers is 81.

What is the average of n numbers a₁, a₂, ..., aₙ?

The average of the numbers a₁, a₂, ..., aₙ is calculated as

Average = (a₁ + a₂ + ··· + aₙ) / n.

Given

Average of the four numbers = 85,

The largest of the four numbers is 97.

Find the sum of all the four numbers

Let the four numbers be a, b, c, and d. Then, using their given average,

(a + b + c + d) / 4 = 85

⇒  a + b + c + d = 85 × 4 = 340.

Find the sum of the numbers excluding the largest one

Let the largest number be d. So, d = 97. Then, the sum of the remaining three is

a + b + c = 340 - d = 340 - 97 = 243.

Find the average of the three numbers

Using the above definition average of the remaining three numbers is calculated as

Av(a,b,c) = (a + b + c)/3 = 243 / 3 = 81.

The required average of the remaining three numbers is 81.

Learn more about the average here

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