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The length of the segment EF is 12 cm. What is the length of ED? *
DE = 6 SqRt 3 cm

DE = 3 SqRt 12 cm

DE = 6 SqRt 12 cm


DE = 3 SqRt 3 cm

WHO ANSWERS WILL BE MARK AS BRAINLIEST The length of the segment EF is 12 cm What is the length of ED DE 6 SqRt 3 cm DE 3 SqRt 12 cm DE 6 SqRt 12 cm DE 3 SqRt 3 class=

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Space

Answer:

ED = 6√3 cm

Step-by-step explanation:

This is a 30-60-90 triangle. Remember the rules. Hypotenuse is always 2x. Leg across from 60° is x√3. Leg across from 30° is x.

12 = 2x

x = 6

ED = x√3

ED = 6√3

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