Answer: -8.93
Step-by-step explanation:
Given the function:
N(X) = 90(0.86)^x+ 69
X in the interval [0, 6]
For X = 0
N(0) = 90(0.86)^0 + 69
90 + 69 = 159
For X = 6
N(6) = 90(0.86)^6 + 69
90(0.404567235136) + 69
= 105.41105116224
Therefore, average change of change in temperature ;
(temp 2 - temp 1) / ( time 2 - time)
(105.41105116224 - 159) / (6 - 0)
= - 53.58894883776 / 6
= - 8.93149147296
= - 8.93
The approximate average rate of change of the temperature of the hot chocolate, in degrees per minute, over the interval [0, 6] is;
Option 1; -8.93
We are given the function;
N(x) = 90(0.86)ˣ + 69
We want to find the average rate of change over the interval (0, 6).
Thus;
N(0) = 90(0.86)⁰ + 69
N(0) = 90 + 69
N(0) = 159°
N(6) = 90(0.86)⁶ + 69
N(6) = 105.411°
Formula for rate of change is;
Rate of change = Δy/Δx
Thus; Rate of change = (159 - 105.411)/(0 - 6)
Rate of change = -8.93
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