A researcher predicts that listening to music while solving math problems will make a particular brain area more active. To test this, a research participant has her brain scanned while listening to music and solving math problems, and the brain area of interest has a percentage signal change of 58. From many previous studies with this same math problems procedure (but not listening to music), it is known that the signal change in this brain area is normally distributed with a mean of 35 and a standard deviation of 10. (a) Using the .01 level, what should the researcher conclude

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Answer:

As the P-value (0.0107) is bigger than the significance level (0.01), the effect is not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that listening to music while solving math problems will make a particular brain area more active.

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that listening to music while solving math problems will make a particular brain area more active.

Then, the null and alternative hypothesis are:

[tex]H_0: \mu=35\\\\H_a:\mu> 35[/tex]

The significance level is 0.01.

The sample has a size n=1.

The sample mean is M=58.

The standard deviation of the population is known and has a value of σ=10.

We can calculate the standard error as:

[tex]\sigma_M=\dfrac{\sigma}{\sqrt{n}}=\dfrac{10}{\sqrt{1}}=10[/tex]

Then, we can calculate the z-statistic as:

[tex]z=\dfrac{M-\mu}{\sigma_M}=\dfrac{58-35}{10}=\dfrac{23}{10}=2.3[/tex]

This test is a right-tailed test, so the P-value for this test is calculated as:

[tex]\text{P-value}=P(z>2.3)=0.0107[/tex]

As the P-value (0.0107) is bigger than the significance level (0.01), the effect is not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that listening to music while solving math problems will make a particular brain area more active.