Respuesta :

Answer:

Step-by-step explanation:

hello,

let s assume that we are on [tex][0;+\infty[[/tex]

[tex]f(x)=x^2[/tex]

if you are looking for

[tex]g(x)=f^{-1}(x)[/tex]

then

[tex]g(x)=\sqrt{x}[/tex]