Answer:
ab = 2
Step-by-step explanation:
Given equations
ax² +ax + 2 = 0
x² + x + b = 0
root of both the equation
x= 1
then we can plug in x = 1 in both the equation
ax² +ax + 2 = 0 x² + x + b = 0
a*1² +a*1 + 2 = 0 1² + 1 + b = 0
a +a + 2 = 0 1 + 1 + b = 0
2a + 2 = 0 2 + b = 0
2a = - 2 b = -2
a = -2/2 = -1
Thus,
a = -1
b = -2
a*b = -1*-2 = 2
ab = 2
