Answer:
-4
Step-by-step explanation:
Hello,
let say that [tex]x_1[/tex] and [tex]x_2[/tex] are two zeros of second order polynomial
it can be then be written
[tex](x-x_1)(x-x_2)=x^2-(x_1+x_2)x+x_1*x_2[/tex]
So when we check this expression
[tex]x^2+4x+7[/tex]
we can say that the sum of zeros is -4
and the the product of zeros is 7
to note that in this example there are no real root of this equation
[tex]x^2+4x+7=0[/tex]
here, the zeros are complex numbers not real ones
if I have to solve it in [tex]\mathbb{R}[/tex] I would say that there are no zeros so their sum is not defined
if I have to solve it in [tex]\mathbb{C}[/tex] I would say that there are two complex roots and their sum is -4
hope this helps
