Answer:
Step-by-step explanation:
x + y = 5 ---(1)
2x - y = 3 ---(2)
adding both the equation
=> (x+y)+(2x-y) = 5 + 3
=> x + y + 2x - y = 8
=> 3x = 8
=> x = 8/3
by substitution methodsubstitute the value of x in equation (2)
=> 2x - y = 3
=> 2×8/3 - y = 3
=> 16/3 - y = 3
=> 16/3 - 3 = y
=> y = 16 - 9/3
=> y = 7/3
Verification :-
Putting the value of x and y in both the equation
x + y = 5
LHS
=> 8/3 + 7/3
=> 8+7/3
=> 15/3 = 5 = RHS verified
2x - y = 3
(LHS )
__> 2×8/3 - 7/3
and then
__> 16/3 - 7/3
__>16-7/3
__>9/3 = 3 = RHS verified
