Answer:
The final temperature is T2= 5.35°C
Explanation:
Apply the Gay-lussacs's law we have
[tex]\frac{P1}{T1} = \frac{P2}{T2}[/tex]
P1, initial pressure= 5.00 x 10^6 Pa
T1, initiation temperature= 25.°C
P2, final pressure= 1.07 x 10^6 Pa
T2, final temperature= ?
[tex]\frac{5.00 * 10^6}{25} =\frac{1.07 *10^6}{T2} \\[/tex]
Cross multiplying and making T2 subject of formula we have
[tex]T2 =\frac{1.07 *10^6*25}{5.00 * 10^6} \\\\T2= \frac{26.75}{5} \\T2= 5.35[/tex]
T2= 5.35°C
