Answer:
0.5934% probability that a baseball player will play at an NCAA college and will also go on to be drafted by the MLB
Step-by-step explanation:
We use the conditional probability formula to solve this question. It is
[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]
In which
P(B|A) is the probability of event B happening, given that A happened.
[tex]P(A \cap B)[/tex] is the probability of both A and B happening.
P(A) is the probability of A happening.
In this question:
Event A: Playing at an NCAA college.
Event B: Being drafted by the MLB.
6.9% will play in an NCAA college
This means that [tex]P(A) = 0.069[/tex]
8.6% of the college players will go on to be drafted by the MLB.
This means that [tex]P(B|A) = 0.086[/tex]
What is the probability that a baseball player will play at an NCAA college and will also go on to be drafted by the MLB?
[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]
[tex]P(A \cap B) = P(A) \times P(B|A)[/tex]
[tex]P(A \cap B) = 0.069*0.086 = 0.005934[/tex]
0.5934% probability that a baseball player will play at an NCAA college and will also go on to be drafted by the MLB
