Answer:
[tex]40^\circ,50^\circ$ and 90^\circ[/tex]
[tex]42^\circ,66^\circ$ and 72^\circ[/tex]
[tex]60^\circ,60^\circ$ and 60^\circ[/tex]
Step-by-step explanation:
The sum of angles in a triangle is 180 degrees
(a)Given the angles 40° and 50°
The third angle is, therefore: [tex]180^\circ-(40^\circ+50^\circ)=90^\circ[/tex]
We, therefore, have the set: [tex]40^\circ,50^\circ$ and 90^\circ[/tex]
(b)Given the angles 42° and 66°
The third angle is, therefore: [tex]180^\circ-(42^\circ+66^\circ)=72^\circ[/tex]
We, therefore, have the set: [tex]42^\circ,66^\circ$ and 72^\circ[/tex]
(c)Given the angles 60° and 60°
The third angle is, therefore: [tex]180^\circ-(60^\circ+60^\circ)=60^\circ[/tex]
We, therefore, have the set: [tex]60^\circ,60^\circ$ and 60^\circ[/tex]
