Answer:
(0, - 5 ) and (2, - 1 )
Step-by-step explanation:
Given the 2 equations
y = 2x - 5 → (1)
y = x² - 5 → (2)
Substitute y = x² - 5 into (1)
x² - 5 = 2x - 5 ( subtract 2x - 5 from both sides )
x² - 2x = 0 ← factor out x from each term
x(x - 2) = 0
Equate each factor to zero and solve for x
x = 0
x - 2 = 0 ⇒ x = 2
Substitute these values into (1) for corresponding values of y
x = 0 : y = 2(0) - 5 = 0 - 5 = - 5 ⇒ (0, - 5 )
x = 2 : y = 2(2) - 5 = 4 - 5 = - 1 ⇒ (2, - 1 )
Answer:
y=2x-5 ......... 1
y = x² - 5 ......... 2
Substitute equation 1 into equation 2
You'll get
2x - 5 = x ² - 5
x² - 2x = -5 + 5
x² - 2x = 0
Factorize
x ( x - 2 ) = 0
x = 0 x = 2
Now put the values of x into any of the equation
When x = 0
y = 2(0) - 5
y = 5
When x = 2
y = 2(2) - 5
y = 4 - 5
y = -1
When x = 0 y = - 5
When x = 2 y = - 1
Hope this helps
