Respuesta :
Answer: The final temperature will be [tex]70^0C[/tex]
Explanation:
To calculate the specific heat of substance during the reaction.
[tex]q=m\times c\times (T_{final}-T_{initial})[/tex]
where,
q = heat absorbed =41840 J
c = specific heat = [tex]4.184J/g^0C[/tex]
m = mass of water = 200 g
[tex]T_{final}[/tex] = final temperature =?
[tex]T_{initial}[/tex]= initial temperature = [tex]20^0C[/tex]
Now put all the given values in the above formula, we get:
[tex]41840J=200g\times 4.184J/g^0C\times (T_{final}-20)^0C[/tex]
[tex]T_{final}=70^0C[/tex]
Thus the final temperature will be [tex]70^0C[/tex]
The final temperature will be [tex]70^oC[/tex]
Specific heat capacity
It is defined as the heat capacity of a sample of the substance divided by the mass of the sample.
Formula to calculate specific heat capacity:
- [tex]q=m*C*(T_2-T_1)[/tex]
where,
q = heat absorbed =[tex]41840 J[/tex]
C = specific heat = [tex]4.184 J/g^oC[/tex]
m = mass of water = [tex]200 g[/tex]
T₁= initial temperature = [tex]20^oC[/tex]
To find:
T₂= final temperature =?
Now put all the given values in the above formula, we get:
[tex]q=m*C*(T_2-T_1)\\\\41840J=200g*4.184J/g^oC(T_2-20^oC)\\\\T_2=70^oC[/tex]
Thus, the final temperature will be [tex]T_2=70^oC[/tex]
Learn more:
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