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The claim is that the proportion of drowning deaths of children attributable to beaches is more than 0.25, and the sample statistics include n = 696 drowning deaths of children with 30% of them attributable to beaches. Find the value of the test statistic z.

Respuesta :

Answer:

The test statistic Z = 3.125

Step-by-step explanation:

Given Population proportion P = 0.25

Given sample size 'n' = 696

Sample proportion 'p⁻' = 0.30

Test statistic

                 [tex]Z = \frac{p^{-} -P}{\sqrt{\frac{P Q}{n} } }[/tex]

                 [tex]Z = \frac{0.30-0.25}{\sqrt{\frac{0.25 X 0.75}{696} } } = 3.125[/tex]

Final answer:-

The test statistic Z = 3.125

The value of the test statistic z is 3.05.

  • The calculation is as follows:

The standard deviation is

[tex]= \sqrt{ \frac{P\times (1 - P)}{n} }\\\\= \sqrt{\frac{0.25 \times (1 - 0.25)}{696} }[/tex]

= 0.0164

Now

the value of test statistics is

[tex]= \frac{(0.3) - 0.25}{0.0164}[/tex]

= 3.05

Therefore we can conclude that The value of the test statistic z is 3.05.

Learn more: brainly.com/question/17429689

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