Answer:
b) -1/9
Step-by-step explanation:
Given
[tex]a_{n} = \frac{(-1)^{n} }{2n-1}[/tex]
First term
[tex]a_{1} = \frac{(-1)^{1} }{2(1)-1} = -1[/tex]
second term
[tex]a_{2} = \frac{(-1)^{2} }{2(2)-1} = \frac{1}{3}[/tex]
Third term
[tex]a_{3} = \frac{(-1)^{3} }{2(3)-1} = \frac{-1}{5}[/tex]
Fourth term
[tex]a_{4} = \frac{(-1)^{4} }{2(4)-1} = \frac{1}{7}[/tex]
Fifth term
[tex]a_{5} = \frac{(-1)^{5} }{2(5)-1} = \frac{-1}{9}[/tex]
