Answer:
In this triangle, the product of sin B and tan C is c/a or cos B, and the product of sin C and tan B is b/a cos C. We determine these as follows:
sin B tan C = b/a (c/b) = c/a
sin C tan B = c/a (b/c) = b/a
Hope this answers the question. Have a nice day.
Step-by-step explanation:
DONT NOW AM NO SURE
The product of sin B and tan C is c/a, and the product of sin C and tan B is a/a
From the triangle, we have:
sin(B) = b/a
tan(C) = c/b
sin(C) = c/a
tan(B) = b/c
So, we have:
sin(B) * tan(C) = b/a * c/b
Evaluate
sin(B) * tan(C) = c/a
Also, we have:
sin(C) * tan(B) = c/a * b/c
Evaluate
sin(C) * tan(B) = b/a
Hence, the product of sin B and tan C is c/a, and the product of sin C and tan B is a/a
Read more about right triangles at:
https://brainly.com/question/2217700
#SPJ5
