Answer:
ФE = 9.403W
Explanation:
In order to calculate the magnitude of the electric flux trough the sheet, you use the following formula:
[tex]\Phi_E=\vec{A}\cdot \vec{E}=AEcos\theta[/tex] (1)
A: area of the rectangular sheet = (0.400m)(0.600m) = 0.24m^2
E: magnitude of the electric field = 95.0N/C
θ: angle between the direction of the electric field and the normal to the surface of the sheet
You replace the values of the parameters in the equation (1):
[tex]\Phi_E=(0.24m^2)(95.0N/m)cos(20\°)=9.304W[/tex]
The magnitude of the electric flux is trough the sheet is 9.403W
