Answer:
The correct answer will be "400.4 N". The further explanation is given below.
Explanation:
The given values are:
Mass of truck,
m = 600 kg
g = 9.8 m/s²
On equating torques at the point O,
⇒ [tex]T\times Cos(10+5)\times (1.3+4)=mg\times Sin(5)\times 4[/tex]
So that,
On putting the values, we get
⇒ [tex]T\times Cos(15^{\circ})\times 5.3=600\times 9.8\times Sin(5^{\circ})\times 4[/tex]
⇒ [tex]T=400.4 \ N[/tex]
