Answer:
Step-by-step explanation:
If v varies jointly as p and q, this means that v varies directly as the product of p and q as shown;
[tex]v \alpha pq[/tex]
[tex]v = kpq[/tex]... 1
k = constant of proportionality
Also v varies inversely as the square of s; mathematically,
[tex]v \alpha \frac{1}{s^{2} } \\v = \frac{k}{s^{2} }... 2[/tex]
Equating 1 and 2, we have;
[tex]v = \frac{kpq}{s^{2} }[/tex]
Given v = 1.6, when p=4.1, q=7 and s=1.3
[tex]k = \frac{vs^{2} }{pq}[/tex]
[tex]k = \frac{1.6*1.3^{2} }{4.1*7}\\k = \frac{2.704}{28.7}\\ k =0.09422[/tex]
The constant of proportionality is 0.09422
The expression therefore becomes [tex]v = \frac{0.09422pq}{s^{2} }[/tex]
