Answer:
The speed is [tex]v_2 = 0.2813 \ m/s[/tex]
Explanation:
From the question we are told that
The mass of the first skater is [tex]m_1 = 45 \ kg[/tex]
The final speed of the first skater is [tex]v_1 = 0.375 \ m/ s[/tex]
The mass of the second skater is [tex]m_2 = 60 \ kg[/tex]
According to the principle of linear momentum conservation
[tex]Initial \ momentum = final \ momentum[/tex]
Here [tex]Initial momentum = (m_1 + m_2) * u[/tex]
Since they they started from a stationary position
[tex]u = 0[/tex]
So
[tex]Initial \ momentum = 0 \ m/s[/tex]
While
[tex]final \ momentum = m_1* v_1 + m_2 * v_2[/tex]
substituting values
[tex]final \ momentum = (45 * 0.375) +(60 * v_2)[/tex]
So [tex](45 * 0.375) +(60 * v_2) = 0[/tex]
=> [tex]v_2 = 0.2813 \ m/s[/tex]
