c) A shopkeeper made a loss of Rs 20 when he sold a bag at 20% discount. If he had sold it at 10% discount, he would have gained 8%. Find the marked price of the bag.
help!!​

Respuesta :

Answer: Marked price Rs. 600

Step-by-step explanation:

Let M be the marked price

1) When shop keeper sold at 20% discount, ie. SP = 0.8M

CP - SP = 20

CP = 20 + SP

CP = 20 + 0.8M

2) When shopkeeper sells at 8% discount, he makes a profit of 10%

SP = 0.9M/1.08

Equating 1 and 2, we get

20 + 0.8M = 0.9M/1.08

21.6 + 0.864M = 0.9M

0.036 M = 21.6

M = 21.6 / 0 036

M = 600

━━━━━━━━━━━━━━━━━━━━━━━━━

[tex]\bf\Huge\red{\mid{\overline{\underline{ ANSWER }}}\mid } [/tex]

━━━━━━━━━━━━━━━━━━━━━━━━━

[tex]\Large\fbox{\color{purple}{QUESTION}}[/tex]

A shopkeeper made a loss of Rs 20 when he sold a bag at 20% discount. If he had sold it at 10% discount, he would have gained 8%. Find the marked price of the bag.

━━━━━━━━━━━━━━━━━━━━━━━━━

[tex]\Large\fbox{\color{purple}{ SOLUTION }}[/tex]

let M, S and C be the mark price, selling price & cost price respectively.

1) when shopkeeper sells at 20% discount then he suffers a loss of rupees 20 then we have :-

[tex]s = ( 1 - \frac{20}{100} ) \times m = 0.8m \\ \\ and \: c - s = 20[/tex]

C = 20 + 0.8 m ------------- eq 1

2) when shopkeeper sells at 20% discount then he makes a profit of 8% then we have

[tex]s = ( 1 - \frac{10}{100} ) \times m = 0.9m \\ \\ and \\ \\ s = ( 1 + \frac{8}{100} ) \times c = \: \frac{0.9m}{1.08} [/tex]

since the cost price of bag doesn't change and equating 1 and 2 we get

[tex]20 + 0.8m = \frac{0.9m}{1.08} \\ \\ 21.6 + 0.864m \: = 0.9m \\ \\ 0.036m \: = 21.6 \\ \\ m \: = 600[/tex]

hence ur answer is rupees 600

━━━━━━━━━━━━━━━━━━━━━━━━━

[tex]\bf\Large\red{ THANKS \: FOR \: YOUR}[/tex]

[tex]\bf\Large\red{ QUESTION \: HOPE \: IT } [/tex]

[tex]\bf\Large\red{ HELPS }[/tex]

[tex]\Large\mathcal\green{FOLLOW \: ME} [/tex]

━━━━━━━━━━━━━━━━━━━━━━━━━