Answer:
Option (3)
Step-by-step explanation:
Explicit formula of the sequence is,
[tex]a_n=3^n+4[/tex]
From this explicit formula,
First term of the sequence will be,
[tex]a_1=(3^1)+4[/tex]
[tex]a_1=7[/tex]
Second term of the sequence,
[tex]a_2=(3^2)+4[/tex]
[tex]a_2[/tex] = 13
3rd term of the sequence,
[tex]a_{3}=(3^3)+4[/tex]
= 31
Sequence formed,
7, 13, 31 ..........
From the given options,
Recursive formula,
[tex]a_n=3a_{n-1}-8[/tex]
[tex]a_2=3(a_1)-8[/tex]
[tex]a_2=3(7)-8[/tex]
[tex]a_2=21-8[/tex] = 13
[tex]a_3=3a_2-8[/tex]
[tex]a_3=3a_2-8[/tex]
[tex]a_3=3(13)-8[/tex]
= 39 - 8
= 31
Sequence formed from this recursive formula will be,
7, 13, 31........
Therefore, Option (3) will be the answer.
