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You open a bag of M&M candies to find that it contains 2 green, 4
yellow, 6 brown, and 3 red pieces of candy. If you were going to
randomly eat an M&M from the bag, what is P(~yellow)? (type
your answer in the box below - round to 3 decimal places)

Respuesta :

Answer:

p ( r, y )

  [tex]\frac{4}{10}[/tex] x  [tex]\frac{3}{10}[/tex] = [tex]\frac{12}{100}[/tex]÷[tex]\frac{4}{4}[/tex]

[tex](\frac{3}{25})[/tex]

Step-by-step explanation:

Not sure if it's right.

ZJSG09112007

Answer:

P = 0.267

Step-by-step explanation:

[tex]2 -green\\4- yellow,\\ 6- brown\\ 3- red pieces\\Probability = Event/Total possible Outcomes \\Event = 4\\Total-possible-outcome = 2+4+6+3 =15\\Probabillty = 4/15\\Probabillty = 0.26666666\\Probability = 0.267[/tex]

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