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How many moles of AlF3 are present if a scientist isolates 1.28 x 10^27 molecules of AlF3? Show your work in the space below

4.00 moles

2,126 moles

0.00341 moles

2.00 moles

Respuesta :

Stephen46

Answer:

The answer is 2,126 moles

To find the number of moles we use the formula;

N = n × L

where

N is the number of entities

n is the number of moles

L is the Avogadro's constant which is

6.023 × 10^23

n = N / L

N = 1.28 x 10^27 molecules

n = 1.28 x 10^27 / 6.023 × 10^23

n =2126.245

n = 2,126moles

Hope this helps