Answer:
0.6 = 60% probability that the waiting time for this train is more than 4 minutes on a given day
Step-by-step explanation:
An uniform probability is a case of probability in which each outcome is equally as likely.
For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.
The probability that we find a value X higher than x is given by the following formula.
[tex]P(X > x) = \frac{b - x}{b-a}[/tex]
The waiting time for a train has a uniform distribution between 0 and 10 minutes.
This means that [tex]a = 0, b = 10[/tex]
What is the probability that the waiting time for this train is more than 4 minutes on a given day?
[tex]P(X > x) = \frac{b - x}{b-a}[/tex]
[tex]P(X > 4) = \frac{10 - 4}{10 - 0} = 0.6[/tex]
0.6 = 60% probability that the waiting time for this train is more than 4 minutes on a given day
