1) Uma pessoa saiu de casa indo as compras com R$240,00 na carteira, sendo que gastou no supermercado 2/3 deste valor, em seguida gastou 14 do que havia sobrado na farmácia. Em uma parada no açougue, deixou mais 72 do que lhe havia sobrado. Após estas despesas qual o valor que lhe havia sobrado. Após estas despesas qual o valor restante na carteira dessa pessoa? A)R$ 40,00 B)R$ 30,00 C)R$ 20,00 D)R$ 1000 E)R$ 5,00

We are given that a person left the house to go shopping with $240.00 in his wallet, and he spent 2/3 of this amount in the supermarket, then spent 1/4 of what was left in the pharmacy. At a stop at the butcher shop, he left 1/2 than he had left.

And we have to find the remaining money in the wallet after making all these above expenses.

At the starting, the amount of money in the person's wallet = $240

Amount of money spent in the supermarket = [tex]\frac{2}{3} \text{ of } \$240[/tex]

= [tex]\frac{2}{3} \times 240[/tex]

= [tex]2 \times 80[/tex] = $160

So, now the amount of money left with him = $240 - $160

= $80

Amount of money spent in the pharmacy = [tex]\frac{1}{4} \text{ of } \$80[/tex]

= [tex]\frac{1}{4} \times 80[/tex] = $20

So, now the amount of money left with him = $80 - $20

= $60

Now, Amount of money spent at the butcher shop = [tex]\frac{1}{2} \text{ of } \$60[/tex]

= [tex]\frac{1}{2} \times 60[/tex] = $30

So, now the amount of money left with him = $60 - $30

= $30

Hence, the amount of money remaining in the person's wallet is $30.