Answer:
Answer is given below with explanations.
Step-by-step explanation:
[tex]a \: bag \: has \: 5\: apples \: , \:10 \: oranges \: and \: 5 \: peaches \\ n(S) = 5 + 10 + 5 \\ n(S) = 20 \\ let \: A \: be \: an \: event \: of \: pulling \: out \: an \: apple \\ P(A) = \frac{n(A)}{n(S)} \\ n(A) = 5 \\ P(A) = \frac{5}{20} \\ (reduced \: fraction) = \frac{1}{4} \\ (decimal) = 0.25 \: percent \\ this \: is \: an \: example \: of \\ \: theoritical \: probability \\ sample \: space \: is \: given \: in \: image\\ in \: this \: case \: this \: event \: is \: compound \: event. \\ let \: O \: be \: an \: event \: of \: pulling \: an \: orange \: ball \\ n(O) = 10 \\ P(O) = \frac{n(O)}{n(S)} \\ P(O) = \frac{10}{20} \\ (reduced \: fraction \: ) = \frac{1}{2} \\ decimal = 0.50 \: percent \\ the \: pulling \: of \: orange \: is \: more \: likely \: to \: occur. \\ because \: it \: has \: highest \: probability \: percentage.[/tex]
